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Old 07-07-2006, 12:47 AM   #1 (permalink)
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Default Spatial: Sticky-Sided Dice (Hard)

Competition ends on Monday 31st July 2006 at midnight UK time.

Benny will donate 1000 tokens to the first person who posts the correct solution and explanation to the following problem:

This problem is identical to Spatial: Sticky-Sided Dice (Easy), except that two faces can only be stuck together if their spots total 7. :twisted:
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Old 07-07-2006, 01:09 AM   #2 (permalink)
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G=120
L=56

How did I go this time? ;-)
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Old 07-07-2006, 09:28 AM   #3 (permalink)
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G = 119
L = 84

Cheers,
M
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Old 07-07-2006, 10:47 AM   #4 (permalink)
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Damn, too late. Just come out of meeting.


I get the same figures as mr mojorisin.
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Old 07-07-2006, 01:35 PM   #5 (permalink)
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Well my best answers were:

L=84
G=119

So let's see how you got your answers Hyno :!: :?:
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Old 08-07-2006, 08:36 AM   #6 (permalink)
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You guys are right. I made an error with the first one & did the maths for 6 dice with the second one.

That's what you get for rushing things. ops:
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Old 08-07-2006, 09:38 AM   #7 (permalink)
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Quote:
Originally Posted by mrmojorisin
G = 119
L = 84
Can you give your explanation now?
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Old 09-07-2006, 12:29 PM   #8 (permalink)
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the opposite sides of a regular dice add up to seven. So no matter how you stack them up (assuming the sides stuck together add up to seven), the open sides will always total to a multiple of seven. It also doesnt matter which sides you stick in this case, since they all add up to seven.

The lowest total will obviously again come from arranging them as a large cube. This cube has 12 pairs of dice faces. Each pair adds up to seven. So the total is 7x12 = 84.

The highest total comes from exposing the maximum number of faces - arranging them in a straight line. In this case, there are 17 pairs of dice faces exposed. So the total is 7x17 = 119.

Cheers,
M
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Old 09-07-2006, 01:12 PM   #9 (permalink)
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That's great - thanks! Tokens on their way

Not as difficult as I'd anticipated, after all! ops:
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