Spatial: Sticky-Sided Dice (Easy)

[Benny]

Competition ends on Monday 31st July 2006 at midnight UK time.

Benny will donate 500 tokens to the first person who posts the correct solution and explanation to the following problem:

Suppose I have 8 regular dice (i.e. with spots to indicate the values on the faces) which happen to be have sticky sides so that they can be stuck together. For example:



Assume that the dice only stick together if the sides of them are perfectly aligned (i.e. no tricks by sticking them together at funny angles, etc.). What is the greatest (G) and least (L) amount of spots viewable if all 8 dice are stuck together into 1 shape and suspended by a thread (so that any spots on faces which are not stuck together are assumed to be viewable)?

Answers should be of the form:

G=
L=

To clarify: The shape for L and the shape for G are different, otherwise L would be the same as G.

Please DO NOT explain your answers in your guess posts, but be prepared to explain them when I have confirmed your answers as correct! ;-)

[Hyno]

G=148
L=48

That should be correct? :-?

[Benny]

Very fast and correct!
(My highest answer was actually less, but now I see why yours is possible.)

Time for you to explain ;-)

[Hyno]

With the lower one you stick the dice in 2 x 4 dice square blocks and stick both blocks together so only 3 sides per dice show. Make sure that sides 1, 2 and 3 are showing. 6 dots per dice x 8 dice = 48 dots.

With the higher one make a lightning bolt shape and manouvre the dice so that 1 and 2 are concealed. On the end ones only the 1 should be concealed. The sum is 20+18+18+18+18+18+18+20=148.


Simple!!! ;-)

[Benny]

Correct! Tokens on their way!

Originally Posted by Hyno

Simple!!! ;-)

I did label this one as "(easy)" for a reason ;-)