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#1 (permalink) | |||||||||||
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Administrator
My Mood:
Join Date: Jun 2003
Location: Wigan, UK
Posts: 3,041
Credits: 13,610
Nominated 6 Times in 6 Posts
TOTW/F/M Award(s): 0
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I will give 40 tokens to the first person to explain and provide the correct answer to the following question:
You are just served a hot cup of coffee and want it to be as hot as possible later. If you like milk in your coffee, should you add it when you get the cup or just before you drink it? Mike ... |
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#2 (permalink) |
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Guest
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I think it depends on the temperature of the milk, if ytou have just take the bottle of milk out of the refrigerator it is better to wait just before you want to drink the coffe in order to put the milk on it. But if you have boiled the milk and the temperature of the milk is higher than the coffe ones you can put it just right now because due to the termodinamic rules the coffe will balance the temperature with the milk ones and then gradually go down depending on the time you wait until you drink it. Is this correct? :?: :?: :?:
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#3 (permalink) | |||||||||||
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Administrator
My Mood:
Join Date: Jun 2003
Location: Wigan, UK
Posts: 3,041
Credits: 13,610
Nominated 6 Times in 6 Posts
TOTW/F/M Award(s): 0
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Rafael,
Your answer has the general idea so I will give you the 40 tokens and the answer (As I understand it). Normalize your temperature scale so that 0 degrees = room temperature. Assume that the coffee cools at a rate proportional to the difference in temperature, and that the amount of milk is sufficiently small that the constant of proportinality is not changed when you add the milk. An early calculus homework problem is to compute that the temperature of the coffee decays exponentially with time, T(t) = exp(-ct) T0, where T0 = temperature at t=0. Let l = exp(-ct), where t is the duration of the experiment. Assume that the difference in specific heats of coffee and milk are negligible, so that if you add milk at temperature M to coffee at temperature C, you get a mix of temperature aM+bC, where a and b are constants between 0 and 1, with a+b=1. (Namely, a = the fraction of final volume that is milk, and b = fraction that is coffee.) If we let C denote the original coffee temperature and M the milk temperature, we see that Add milk later: aM + blC Add milk now: l(aM+bC) = laM+blC The difference is d=(1-l)aM. Since l<1 and a>0, we need to worry about whether M is positive or not. M>0: Warm milk. So d>0, and adding milk later is better. M=0: Room temp. So d=0, and it doesn't matter. M<0: Cold milk. So d<0, and adding milk now is better. Of course, if you wanted to be intuitive, the answer is obvious if you assume the coffee is already at room temperature and the milk is either scalding hot or subfreezing cold. Moral of the story: Always think of extreme cases when doing these puzzles. They are usually the key. Oh, by the way, if we are allowed to let the milk stand at room temperature, then let r = the corresponding exponential decay constant for your milk container. Add acclimated milk later: arM + blC We now have lots of cases, depending on whether r<l: The milk pot is larger than your coffee cup. (E.g, it really is a pot.) r>l: The milk pot is smaller than your coffee cup. (E.g., it's one of those tiny single-serving things.) M>0: The milk is warm. M<0: The milk is cold. Leaving out the analysis, I compute that you should... Add warm milk in large pots LATER. Add warm milk in small pots NOW. Add cold milk in large pots NOW. Add cold milk in small pots LATER. Of course, observe that the above summary holds for the case where the milk pot is allowed to acclimate; just treat the pot as of infinite size. You can now relax your brain Mike ... :-k |
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