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#1 (permalink) |
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Guest
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Juan Carlos will also give 250 tokens to the first person who posts the correct solution to the following problem:
The aim of this game is to obtain number six operating with the same number repeated three time. For example, let's consider number 2: if we try to calcute 2+2+2 the result is 6. You should obtain number 6, using three 1's, three 2's, three 3's, ..., three 9's: 1 1 1 = 6 2 2 2 = 6 -> 2 + 2 + 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6 I hope the instructions are clear enough. Good luck. JC PS: Let me make a suggestion, don't begin with number 1 because it is the most difficult one. PS: Will The Guru find the solution? |
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#2 (permalink) |
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Guest
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I think i have the solution to this game:
- (1+1+1)!=3!=3*2*1=6 - 2+2+2=6 - 3*3-3=6 - 4+4- square root(4)=8-2=6 - 5+(5/5)=6 - 6+6-6=6 - 7-(7/7)=6 - cube root (8)+ cube root(8)+cube root(8)=2+2+2=6 - sqrt(9)*sqrt(9)-sqrt(9)=3*3-3=6 In the case I have solved the problem correctly give me the tokens baby :mrgreen: [-X |
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