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Forum Competitions Competitions, Tests and Challenges. Winners will be awarded Tokens

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Old 08-03-2004, 04:55 PM   #1 (permalink)
Juan Carlos
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Default Maths: Number 6

Juan Carlos will also give 250 tokens to the first person who posts the correct solution to the following problem:

The aim of this game is to obtain number six operating with the same number repeated three time.

For example, let's consider number 2: if we try to calcute 2+2+2 the result is 6.

You should obtain number 6, using three 1's, three 2's, three 3's, ..., three 9's:

1 1 1 = 6
2 2 2 = 6 -> 2 + 2 + 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

I hope the instructions are clear enough.

Good luck.

JC

PS: Let me make a suggestion, don't begin with number 1 because it is the most difficult one.

PS: Will The Guru find the solution?
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Old 08-03-2004, 10:06 PM   #2 (permalink)
rafael
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I think i have the solution to this game:

- (1+1+1)!=3!=3*2*1=6
- 2+2+2=6
- 3*3-3=6
- 4+4- square root(4)=8-2=6
- 5+(5/5)=6
- 6+6-6=6
- 7-(7/7)=6
- cube root (8)+ cube root(8)+cube root(8)=2+2+2=6
- sqrt(9)*sqrt(9)-sqrt(9)=3*3-3=6

In the case I have solved the problem correctly give me the tokens baby
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